Rajasthan Board RBSE Solutions for Class 7 Maths Chapter 9 परिमेय संख्याएँ Ex 9.2 Textbook Exercise Questions and Answers.
Rajasthan Board RBSE Solutions for Class 7 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 7. Students can also read RBSE Class 7 Maths Important Questions for exam preparation. Students can also go through RBSE Class 7 Maths Notes to understand and remember the concepts easily. Students can access the data handling class 7 extra questions with answers and get deep explanations provided by our experts.
प्रश्न 1.
योग ज्ञात कीजिए :
(i) \(\frac{5}{4}+\left(\frac{-11}{4}\right)\)
हल:
\(\frac{5}{4}+\left(\frac{-11}{4}\right)=\frac{5+(-11)}{4}\)
= \(\frac{-6}{4}=\frac{-3}{2}\)
(ii) \(\frac{5}{3}+\frac{3}{5}\)
हल:
\(\frac{5}{3}+\frac{3}{5}=\frac{25+9}{15}=\frac{34}{15}\)
(iii) \(\frac{-9}{10}+\frac{22}{15}\)
हल:
(iv) \(\frac{-3}{-11}+\frac{5}{9}\)
हल:
(v) \(\frac{-8}{19}+\frac{(-2)}{57}\)
हल:
(vi) \(\frac{-2}{3}\) + 0
हल:
\(\frac{-2}{3}\) + 0 = \(\frac{-2}{3}\)
(vii) -2 \(\frac{1}{3}\) + 4 \(\frac{3}{5}\)
हल:
प्रश्न 2.
ज्ञात कीजिए :
(i) \(\frac{7}{24}-\frac{17}{36}\)
हल:
(ii) \(\frac{5}{63}-\left(\frac{-6}{21}\right)\)
हल:
(iii) \(\frac{-6}{13}-\left(\frac{-7}{15}\right)\)
हल:
(iv) \(\frac{-3}{8}-\frac{7}{11}\)
हल:
(v) -2 \(\frac{1}{9}\) - 6
हल:
प्रश्न 3.
गुणनफल ज्ञात कीजिए :
(i) \(\frac{9}{2} \times\left(\frac{-7}{4}\right)\)
हल:
\(\frac{9}{2} \times\left(\frac{-7}{4}\right)=\frac{9 \times(-7)}{2 \times 4}=\frac{-63}{8}\)
(ii) \(\frac{3}{10}\) × (-9)
हल:
\(\frac{3}{10}\) × -9 = \(\frac{3 \times(-9)}{10}=\frac{-27}{10}\)
(iii) \(\frac{-6}{5} \times \frac{9}{11}\)
हल:
\(\frac{-6}{5} \times \frac{9}{11}=\frac{(-6) \times 9}{55}=\frac{-54}{55}\)
(iv) \(\frac{3}{7} \times\left(\frac{-2}{5}\right)\)
हल:
\(\frac{3}{7} \times\left(\frac{-2}{5}\right)=\frac{3 \times(-2)}{7 \times 5}=\frac{-6}{35}\)
(v) \(\frac{3}{11} \times \frac{2}{5}\)
हल:
\(\frac{3}{11} \times \frac{2}{5}=\frac{3 \times 2}{11 \times 5}=\frac{6}{55}\)
(vi) \(\frac{3}{-5} \times \frac{-5}{3}\)
हल:
\(\frac{3}{-5} \times \frac{-5}{3}\) = 1
प्रश्न 4.
निम्नलिखित के मान ज्ञात कीजिए :
(i) (-4) ÷ \(\frac{2}{3}\)
हल:
-4 ÷ \(\frac{2}{3}\) = -4 × \(\frac{3}{2}\)
= \(\frac{-4 \times 3}{2}=\frac{-12}{2}\) = -6
(ii) \(\frac{-3}{5}\) ÷ 2
हल:
(iii) \(\frac{-4}{5}\) ÷ (-3)
हल:
(iv) \(\frac{-1}{8} \div \frac{3}{4}\)
हल:
(v) \(\frac{-2}{13} \div \frac{1}{7}\)
हल:
(vi) \(\frac{-7}{12} \div\left(\frac{-2}{13}\right)\)
हल:
(vii) \(\frac{3}{13} \div\left(\frac{-4}{65}\right)\)
हल: