RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4

Rajasthan Board RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 Textbook Exercise Questions and Answers.

Rajasthan Board RBSE Solutions for Class 7 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 7. Students can also read RBSE Class 7 Maths Important Questions for exam preparation. Students can also go through RBSE Class 7 Maths Notes to understand and remember the concepts easily. Students can access the data handling class 7 extra questions with answers and get deep explanations provided by our experts.

RBSE Class 7 Maths Solutions Chapter 12 Algebraic Expressions Ex 12.4

Question 1.
Observe the patterns of digits made from line segments of equal length. You will find such segmented digits on the display of electronic watches or calculators:
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 1
If the number of digits formed is taken to be n, the number of segments required to form n digits is given by the algebraic expression appearing on the right of each pattern.
How many segments are required to form 5, 10, 100 digits of the kind
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 2
Answer:
(a)
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 3
∵ Expression for number of line segments to form ‘n figures of the find
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 3
5n + 1.
∴ For five figures, line segments = 5 × 5 + 1 = 25 + 1 = 26
For 10 figures, line segments = 5 × 10 + 1 = 50 + 1 = 51
For 100 figures, line segments = 5 × 100 + 1 = 500 + 1 = 501

RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4

(b)
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 4
∵ Expression for number of line segments to form n figures of the find
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 4
3n + 1.
∴ For 5 figures, line segments = 3 × 5 + 1 = 15 + 1 = 16
For 10 figures, line segments= 3 × 10 + 1 = 30 + 1 = 31
For 100 figures, line segments = 3 × 100 + 1 = 300 + 1 = 301

(c)
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 5
∵ Expression for number of line segments to form ‘n’ figures of the kind
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 5
5n + 2.
For 5 figures, line segments = 5 × 5 + 2 = 25 + 2 = 27
For 10 figures, line segments = 5 × 10 + 2 = 50 + 2 = 52
For 100 figures, line segments = 5 × 100 + 2 = 500 + 2 = 502

Question 2.
Use the given algebraic expression to complete the table of number patterns:
RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4 6
Answer:
(i) For the expression 2n - 1
The 100th term = 2 × 100 - 1
= 200 - 1 = 199

(ii) For the expression 3n + 2
The 5th term = 3 × 5 + 2 = 15 + 2 = 17
The 10th term = 3 × 10 + 2 = 30 + 2 = 32
The 100th term = 3 × 100 + 2 = 300 + 2 = 302

(iii) For the expression 4n + 1
The 5th term = 4 × 5 + 1 = 20 + 1 = 21
The 10th term = 4 × 10 + 1 = 40 + 1 = 41
The 100th term = 4 × 100 + 1 = 400 + 1 = 401

RBSE Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4

(iv) For the expression 7n + 20
The 5th term = 7 × 5 + 20 = 35 + 20 = 55
The 10th term = 7 × 10 + 20 = 70 + 20 = 90
The 100th term = 7 × 100 + 20 = 700 + 20 = 720

(v) For the expression n2 + 1
The 5th term = 52 + 1 = 25 + 1 = 26
The 10th term = 102 + 1 = 100 + 1 = 101
The 100th term = 1002 + 1 = 10000 + 1 = 10001

Bhagya
Last Updated on June 16, 2022, 4:08 p.m.
Published June 16, 2022