These comprehensive RBSE Class 8 Maths Notes Chapter 6 Square and Square Roots will give a brief overview of all the concepts.
Rajasthan Board RBSE Solutions for Class 8 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 8. Students can also read RBSE Class 8 Maths Important Questions for exam preparation. Students can also go through RBSE Class 8 Maths Notes to understand and remember the concepts easily. Practicing the class 8 maths chapter 6 try these solutions will help students analyse their level of preparation.
→ Square Number: If a natural number m can be expressed as n2, where n is also a natural number, then m is a square number or perfect square.
Ex. 25 is the square of 5, so 25 is a perfect square or square number
→ A number ending in 2, 3, 7 or 8 is never a perfect square. In other words all square numbers end with 0, 1, 4, 5, 6 or 9 at unit’s place.
→ Square numbers can only have even number of zeros at the end.
Ex. 8100 = 902 is a perfect square.
→ A perfect square (other than 1) leaves a remainder 0 or 1 when divided by 3.
→ A perfect square (other than 1), when divided by 4, leaves a remainder 0 or 1.
→ Squares of even numbers are always even.
→ Squares of odd numbers are always odd.
→ The sum of first n odd natural numbers is n2.
→ Any odd number can be expressed as sum of consecutive natural number.
→ If a number has 1 or 9 in the unit’s place, then its square ends with 1.
→ When a square number ends with 6, the number whose square it ils, will have either 4 or 6 in unit’s place.
→ Between n2 and (n + 1)2 there are 2n numbers which is 1 less than the difference of two squares.
→ If a perfect square is of n-digits then its square root will have \(\frac{n}{2}\) digits if n is even or \(\frac{(n+1)}{2}\) if n is odd.
→ Pythagorean Triplets: A triplet m, n and p of three natural numbers is called a Pythagorean triplet, if m2 + n2 = p2
Ex. (7, 24, 25) is a Pythagorean triplet.
Let m = 7; n = 24; p = 25
then 72 + 242 = 252
For any natural number where m > 1 (2m, m2 - 1, m2 + 1) is a Pythagorean triplet.
→ If a and b are any two whole numbers, then
\(\sqrt{a b}=\sqrt{a} \times \sqrt{b}\)
\(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)
→ If x = a2, then √x = a
→ The squares of numbers 1, 11, 111, ..... etc. They give a beautiful pattern:
12 = 1
112 = 121
1112 = 12321
11112 = 1234321
111112 = 123454321
another interesting pattern
72 = 49
672 = 4489
6672 = 444889
66672 = 44448889
666672 = 4444488889