RBSE Class 8 Maths Notes Chapter 14 Factorization

These comprehensive RBSE Class 8 Maths Notes Chapter 14 Factorization will give a brief overview of all the concepts.

Rajasthan Board RBSE Solutions for Class 8 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 8. Students can also read RBSE Class 8 Maths Important Questions for exam preparation. Students can also go through RBSE Class 8 Maths Notes to understand and remember the concepts easily. Practicing the class 8 maths chapter 6 try these solutions will help students analyse their level of preparation.

RBSE Class 8 Maths Chapter 14 Notes Factorization

→ When an algebraic expression can be written as the product of two or more expressions is called a factor of the given expression and this process of finding factors is called factorisation.

→ An irreducible factor is a factor which cannot be expressed further as a product of factors.

→ Factorisation when a conimon monomial factor occurs in each term:
Steps

  1. Find the HCF of all the terms of the given expression;
  2. Divide eath term by the HCF;
  3. Write the given expression as the product of the quotient obtained in step (2) and this HCF.

RBSE Class 8 Maths Notes Chapter 14 Factorization

→ Factorisation by grouping:
Steps

  1. Arrange the terms of the given expression in groups in such a way that all the groups have a common factor;
  2. factorise each group:
  3. Take out the factor which is common to each group.

→ Factorisation when a binomial is common:
Steps

  1. Find the common binomial;
  2. Write the given expression as the product of this binomial and quotient obtained on dividing the given expression by this binomial.

→ Factorisation by using formulae:

  • (a + b)2 = (a + b)(a + b) = a2 + b2 + 2ab
  • (a - b)2 = (a - b)(a - b) = a2 + b2 - 2ab
  • (a + b)(a - b) = a2 - b2
  • (x + a)(x + b) = x2 + (a+b)x + ab
  • (a + b + c)2 = (a + b + c)(a + b + c) = a2 + b2 + c2 + 2ab + 2bc + 2ca
  • (a + b)3 = (a + b)(a + b)(a + b) = a3 + b3 + 3ab (a + b)
  • (a - b)3 = (a - b) (a - b) (a - b) = a3 - b3 - 3ab (a - b)

→ A monomial multiplied by a monomial always gives a monomial. But a monomial divided by a monomial may not give a monomial.

→ If the remainder is zero, both the divisor and the quotient, are factors of the dividend.

→ In case of divisions of algebraic expressions, we have Dividend = Divisor × Quotient + Remainder.

→ We know that in the case of numbers, division is the inverse of multiplication. This idea is applicable also to the division of algebraic expressions.

RBSE Class 8 Maths Notes Chapter 14 Factorization

→ In the case of division of a polynomial by a monomial, we may carry out the divison either by dividing each term of the polynomial by the monomial or by the common factor method.

→ In the case of division of a polynomial by a polynomial, we cannot proceed by dividing each term in the dividend polynomial by the divisor polynomial. Instead, we factorise both the polynomials and cancel the common factors.

→ When you square a monomial, the co-efficient and each factor has to be squared.

Prasanna
Last Updated on June 1, 2022, 2:57 p.m.
Published June 1, 2022