RBSE Solutions for Class 6 Maths Chapter 8 Decimals InText Questions

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 8 Decimals InText Questions Textbook Exercise Questions and Answers.

RBSE Class 6 Maths Solutions Chapter 8 Decimals InText Questions

Question 1.
Can you now write the following numbers as decimals?

Answer:
(i) 5 hundreds + 3 tens + 8 ones + 1 tenths
= 5 × 100 + 3 × 10 + 8 × 1 + 1 × \(\frac{1}{10}\)
= 500 + 30 + 8 + 0.1 = 538.1

(ii) 2 hundreds + 7 tens + 3 ones + 4 tenths = 2 × 100 + 7 × 10 + 3 × 1 + 4 × \(\frac{1}{10}\)
= 200 + 70 + 3 + 0.4 = 273.4

(iii) 3 hundreds + 5 tens + 4 ones + 6 tenths
= 3 × 100 + 5 × 10 + 4 × 1 + 6 × \(\frac{1}{10}\)
= 300 + 50 + 4 + \(\frac{6}{10}\) = 354.6

Question 2.
Write the lengths of Ravi's and Raju's pencils in 'em1 using decimals.
Answer:
Length of Ravi's pencil = 7 cm 5 mm
= 7 cm + 5 mm = 7 cm + \(\frac{5}{10}\) cm {∵ 1 mm = \(\frac{1}{10}\) cm} 
= 7 cm + 0.5 cm = 7.5 cm

Length of Raju's Pencil
= 8 cm 5 mm = 8 cm + 5 mm 5
= 8 cm + cm = 8.5 cm.

Question 3. 
Make three more examples similar to the one given in question 1 and solve them.
Three more examples similar to the one given in question 1 are as follows :
Can you write the following numbers as decimals?

Answer:
1. Required number
= 600 + 40 + 9 + \(\frac{2}{10}\) = 649.2

2. Required number
= 300 + 80 + 4 + \(\frac{5}{10}\) = 384.5

3. Required number
= 400 + 60 + 5\(\frac{7}{10}\) =465.7

(Try These - Page 167)

Question 1.
Write \(\frac{3}{2}, \frac{4}{5}, \frac{8}{5}\) in decimal notation.
Answer:

(Try These - Page 175)

Question 1.
(i) Write 2 rupees 5 paise and 2 rupees 50 paise in decimals.
(ii) Write 20 rupees 7 paise and 21 rupees 75 paise in decimals.
Answer:
(i) 2 rupees 5 paise = 2 rupees + 5 paise
= 2 rupees + \(\frac{5}{100}\)rupee [∵ 1 paise = \(\frac{1}{100}\) rupee]
= 2 rupees + 0.05 rupees 
= 2.05 rupees.

2 rupees 50 paise
= 2 rupees + 50 paise
= 2 rupees + \(\frac{50}{100}\) rupee [∵ 1 paise = \(\frac{1}{100}\) rupee]
= 2 rupees + 0.50 rupee = 2.50 rupees 

(ii) 20 rupees 7 paise = 20 rupee + 7 paise
= 20 rupees + \(\frac{7}{100}\) rupee
= 20 rupees + 0.07 rupee
= 20.07 rupees.

21 rupees 75 paise
= 21 rupee + 75 paise
= 21 rupees + \(\frac{75}{100}\)rupee
= 21 rupees + 0.75 rupee = 21.75 rupees.

(Try These - Page 176)

Question 1.
Can you write 4 mm in 'cm'  using decimals?
Answer:
10 nun = 1 cm
∴ 1 mm = \(\frac{1}{10}\)
∴ 4 mm = 4 × \(\frac{1}{10}\) cm
= \(\frac{4}{10}\) cm = 0.4 cm

Question 2.
How will you write 7 cm 5 mm in 'cm' using decimals?
Answer:
7 cm 5 mm = 7 cm + 5 mm
7 5 = 7 cm + \(\frac{5}{10}\) cm {∵ 1 mm = \(\frac{1}{10}\)cm}
= 7 cm + 0.5 cm = 7.5 cm

Question 3.
Can you now write 52 m as 'km' using decimals? How will you write 340 m as 'km' using decimals? How will you write 2008 m in Tan'?
Answer:
Yes! We can write 52 m as km.
1000 m = 1 km
∴ 52 m = \(\frac{5}{10}\) km {∵ 1 m = \(\frac{1}{1000}\) km}
= 0.052 km

340 m = \(\frac{340}{100}\)km = 0.340 km {∵ 1 m = \(\frac{1}{1000}\) km}

2008 m = (2000 + 8)m
= 2000 m + 8 m 8 1000
= 2 km + 0.008 km
= 2.008 km

(Try These - Page 176)

Question 1.
Can you now write 456 g as 'kg' using decimals?
Answer:
Yes! We can write 456 g as 'kg' using decimals as follow,
456 g = 1000 kg = 0 456 kg {∵ 1g = \(\frac{1}{1000}\) kg}

Question 2.
How will you write 2 kg 9 g in 'kg' using decimals?
Answer:
2 kg 9 g = 2 kg + 9 g
= 2kg + \(\frac{9}{1000}\)kg
{∵ 1 g = \(\frac{1}{1000}\) kg}
= 2 kg + 0.009 kg = 2.009 kg

(Try These - Page 178)

Question 1.
Find:
(i) 0.29 + 0.36
Answer:

Therefore, 0.29 + 0.36 = 0.65

(ii) 0.7 + 0.08
Answer:

Hence, 0.70 + 0.08 = 0.78

(iii) 1.54 + 1.80
Answer:

Hence, 1.54 + 1.80 = 3.34

(iv) 2.66 + 1.85
Answer:

Hence, 2.66 + 1.85 = 4.51

(Try Page -180)

Question 1. 
Subtract 1.85 from 5.46
Answer:

Thus, 5.46 - 1.85 = 3.61

Question 2.
Subtract 5.25 from 8.28
Answer:

Thus, 8.28 - 5.25 = 3.03

Question 3.
Subtract 0.95 from 2.29
Answer:

Thus, 2.29 - 0.95 = 1.34

Question 4.
Subtract 2.25 from 5.68.
Answer:

Thus, 5.68 - 2.25 = 3.43