Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Textbook Exercise Questions and Answers.
Rajasthan Board RBSE Solutions for Class 6 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 6. Students can also read RBSE Class 6 Maths Important Questions for exam preparation. Students can also go through RBSE Class 6 Maths Notes to understand and remember the concepts easily. Students are advised to practice अनुपात और समानुपात के प्रश्न class 6 of the textbook questions.
Question 1.
Draw a line segment of length 7.3 cm using a ruler.
Answer:
Steps of construction :
Question 2.
Construct a line segment of length 5.6 cm using ruler and compasses.
Answer:
Thus XY is the required line segment of length 5.6 cm.
Question 3.
Construct ¯AB of length 7.8 cm. From this, cut off ¯AC of length 4.7 cm. Measure ¯BC.
Answer:
Hence, by measuring ¯BC = 3.1 cm.
Question 4.
Given ¯AB of length 3.9 cm, construct ¯PQ such that 'the length of ¯PQ is twice that of ¯AB, Verify by measurement.
(Hint: Construct PX such that length of PX = length of AB; then cut off XQ such that XQ also has the length of AB.)
Answer:
Steps of Construction :
Thus, the lengths of PX and XQ are added together to make twice the length of AB.
Verification:
Now, by measurement we have: ¯AB + ¯AB = 3.9 cm + 3.9 cm
⇒ 2 (¯AB) = 7.8 cm = ¯PQ
Thus, twice of AB is equal to PQ.
Question 5.
Given ¯AB of length 7.3 cm and ¯CD of length 3.4 cm, construct a line segment ¯XY such that the length of ¯XY is equal to the difference between the lengths of ¯AB and ¯CD. Verify by measurement.
Answer:
Steps of construction :
(4) Now cut off ZY = length of CD = 3.4 cm such that the length XY = Length of AB - length of CD
Verification :
By measurement, we have : XY = 3.9 cm = 7.3 cm - 3.4 cm = AB - CD Thus, we get XY = AB - CD