RBSE Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Textbook Exercise Questions and Answers.

RBSE Class 6 Maths Solutions Chapter 14 Practical Geometry Ex 14.2

Question 1.
Draw a line segment of length 7.3 cm using a ruler.
Answer:
Steps of construction :

• At the point A place the zero mark of the ruler.
• And mark a point B at the exact distance of 7.3 cm from the point A.
• Now join AB.

Question 2.
Construct a line segment of length 5.6 cm using ruler and compasses.
Answer:

• Make a line l. Mark a point X on that line.
• Place the needle of the compasses on the zero mark of the ruler. Use it to mark the pencil point till 5.6 cm mark.
• Place the steel end at the point X and then compasses cut l at Y.

Thus XY is the required line segment of length 5.6 cm.

Question 3. 
Construct $\overline{A B}$ of length 7.8 cm. From this, cut off $\overline{A C}$ of length 4.7 cm. Measure $\overline{B C}$.
Answer:

• Keep the mark zero of this ruler at A.
• Then Y point C is marked at a distance of 4.7 cm from A.
• Then again points C is marked at a distance of 4.7 cm from A.

Hence, by measuring $\overline{B C}$ = 3.1 cm.

Question 4. 
Given $\overline{A B}$ of length 3.9 cm, construct $\overline{P Q}$ such that 'the length of $\overline{P Q}$ is twice that of $\overline{A B}$, Verify by measurement. 

(Hint: Construct PX such that length of PX = length of AB; then cut off XQ such that XQ also has the length of AB.)
Answer:
Steps of Construction :

• Draw a line l.
• Draw AB = 3.9 cm.  
• From the line construct $\overline{P X}$ = $\overline{A B}$ = 3.9 cm.
• Then construct $\overline{X Q}$ = $\overline{A B}$ = 3.9 cm

Thus, the lengths of PX and XQ are added together to make twice the length of AB. 

Verification:
Now, by measurement we have: $\overline{A B}$ + $\overline{A B}$ = 3.9 cm + 3.9 cm
⇒ 2 ($\overline{A B}$) = 7.8 cm = $\overline{P Q}$
Thus, twice of AB is equal to PQ.

Question 5.
Given $\overline{A B}$ of length 7.3 cm and $\overline{C D}$ of length 3.4 cm, construct a line segment $\overline{X Y}$ such that the length of $\overline{X Y}$ is equal to the difference between the lengths of $\overline{A B}$ and $\overline{C D}$. Verify by measurement.
Answer:
Steps of construction :

1. Draw $\overline{A B}$ = 7.3 cm, $\overline{C D}$ = 3.4 cm.
2. Draw a line l and take a point X on it.
3. Then construct XZ such that length of XZ = length $\overline{A B}$ =7.3 cm.

(4) Now cut off ZY = length of CD = 3.4 cm such that the length XY = Length of AB - length of CD

Verification : 
By measurement, we have : XY = 3.9 cm = 7.3 cm - 3.4 cm = AB - CD Thus, we get XY = AB - CD