RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1 Textbook Exercise Questions and Answers.

Rajasthan Board RBSE Solutions for Class 6 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 6. Students can also read RBSE Class 6 Maths Important Questions for exam preparation. Students can also go through RBSE Class 6 Maths Notes to understand and remember the concepts easily. Students are advised to practice अनुपात और समानुपात के प्रश्न class 6 of the textbook questions.

RBSE Class 6 Maths Solutions Chapter 11 Algebra Ex 11.1

Question 1.
Find the rule which gives the number of matchsticks required to make the following matchstick patterns. Use a variable to write the rule.
RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1
Answer:
(a) A patern of letter T = 2n (as two matchsticks used to make letter)
(b) A pattern of letter Z = 3n (as three matchsticks used to make letter)
(c) A pattern of letter U = 3n (as three matchsticks used to make letter)
(d) A pattern of letter V = 2n (as two matchsticks used to make letter)
(e) A pattern of letter E = 5n (as five matchsticks used to make letter)
(f) A pattern of letter S = 5n (as five matchsticks used to make letter)
(g) A pattern of letter A = 6n (as six matchsticks used to make letter)

RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1

Question 2.
We already know the rule for the pattern of letters L, C and F. Some of the letters from Q. 1 (given above) give us the same rule as that given by L. Which are these? Why does this happen?
Answer:
L requires two matchsticks, therefore, pattern of L is 2n. The letter T and V has pattern 2n, since 2 matchsticks are used in all these letters.

Question 3.
Cadets are marching in a parade. There are 5 cadets in arow. What is the rule which gives the number of cadets, given the number of rows? (Use n for the number of rows)
Annswer:
Number of rows = n
Cadets in each row = 5
Therefore, total number of cadets = Number of cadets in a row × total number of rows = 5n

Question 4.
If there are 50 mangoes in a box, how will you write the total number of mangoes in terms of the number of boxes? (Use b for the number of boxes.) Answer:
Number of boxes = 6
Number of mangoes in each box = 50
Therefore, total number of mangoes
= number of mangoes in a box × number of boxes
= 50 × b = 50b

Question 5.
The teacher distributes 5 pencils per student. Can you tell how many pencils are needed, given the number of students? (Use s for the number of students.)
Answer:
Number of students = s
Number of pencils to each student = 5
Therefore, total number of pencils needed
= Number of pencils given to each student × number of pencils
= 5s

RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1

Question 6.
A bird flies 1 km in one minute. Can you express the distance covered by the bird in terms of its flying times in minutes? (Use t for flying time in minutes.)
Answer:
Time taken by bird = t minutes
Speed of bird = 1 km per minute Therefore, distance covered by bird
= Speed of bird × time taken by bird
= 1 × t km = t km.

Question 7.
Radha is drawing a dot Rangoli (a beautiful pattern of lines joining dots) with chalk powder. She has 9 dots in a row. How many dots will her Rangoli have for r rows? How many dots are there if there are 8 rows? If there are 10 rows?
Answer:
Number of rows = r
Number of dots in each row = 9
Total number of dots = Number of rows
x number of dots in each row = 9 × r = 9r
When there are 8 rows, then number of dots
= 9 × 8 = 72 dots When there are 10 rows, then number of dots
= 9 × 10 = 90 dots.

Question 8.
Leela is Radha's younger sister. Leela is 4 years younger than Radha. Can you write Leela's age in terms of Radha's age? Take Radha's age to be x years.
Answer:
Yes!. We can write Leela’s age in terms of Radha’s age.
Radha’s age = x years
Therefore, Leela's age = (x - 4) years.

RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1

Question 9.
Mother has made laddus. She gives some laddus to guests and family members; still 5 laddus remain. If the number of laddus mother gave away is l, how many laddus did she make?
Answer:
Number of laddus given away = l
Number of laddus remaining = 5
Total number of laddus = l + 5.

Question 10.
Oranges are to be transferred from larger boxes into smaller boxes. When a large box is emptied, the oranges from it fill two smaller boxes
and still 10 oranges remain outside. If the number of oranges in a small box are taken to be x. What is the number of oranges in the larger box?
Answer:
Number of oranges in one small box = x
Number of boxes = 2
Therefore, total number of oranges in two small boxes = 2x
Remaining oranges = 10
Thus, number of oranges
= Number of oranges in two small boxes + number of oranges left
= 2x + 10

Question 11.
(a) Look at the following matchstick pattern of squares in fig. The squares are not separate. Two neighbouring squares have a common matchstick. Observe the patterns and find the rule that gives the number of matchsticks in terms of the number of squares. (Hint : If you remove the vertical square at the end, you will get a pattern of Cs.)
RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1 2
Answer:
If we remove 1 from each then they makes table of 3, i.e. 3, 6, 9,12,...
So, the required equation = 3n + 1, where n is number of squares.

RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1

(b) Fig. gives a matchstick pattern of triangles. As in exercise 11 (a) above, find the general rule that gives the number of matchsticks in terms of the number of triangles.
RBSE Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.1 3
Answer:
If we remove 1 from each then they makes table of 2 i.e., 2, 4, 6, 81 ............
So, the required equation = 2n + 1, where n is number of triangles.

Bhagya
Last Updated on June 29, 2022, 1:04 p.m.
Published June 29, 2022