RBSE Solutions for Class 6 Maths Chapter 10 Mensuration InText Questions

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 10 Mensuration InText Questions Textbook Exercise Questions and Answers.

RBSE Class 6 Maths Solutions Chapter 10 Mensuration InText Questions

(Try These - Page 206)

Question 1.
Measure and write the lengths of the four sides of the top of your study table: 
AB = ______ cm 
BC = ______ cm
CD = ______ cm
DA = ______ cm

Now, the sum of the lengths of the four sides
= AB + BC + CD + DA
= ______ cm + ______ cm + ______ cm + ______ cm
= ______ cm
What is the perimeter?
Answer:
The measurement of the four sides of my study table are :
AB = 100 cm, 
BC = 60 cm,
CD = 100 cm, 
DA = 60 cm.
Now, the sum of the lengths of the four sides
= AB + BC + CD + DA
= 100 cm + 60 cm + 100 cm + 60 cm
= 320 cm.

Question 2.
Measure and write the lengths of the four sides of a page of your notebook. The sum of the lengths of the four sides
= AB + BC + CD + DA
= ______ cm + ______ cm + ______ cm + ______ cm
= ______ cm
What is the perimeter of the page?
Answer
Measurement of length of four sides of a page of my notebook is
AB = 30 cm,
BC = 20 cm,
CD = 30 Cm,
DA = 20 cm.

The sum of the lengths of the four sides = AB + BC + CD + DA
= 30 cm + 20 cm + 30 cm + 20 cm
= 100 cm

Question 3.
Meera went to a park 150 m long and 80 m wide. She took one complete round on its boundary. What is the distance covered by her?
Answer:
Length of park = 150 m
Breadth of park = 80 m 
Distance covered by Meera in one complete round
= 150 m + 80 m + 150 m + 80 m 
= 460 m

Question 4.
Find the perimeter of the following figures:
(a) Perimeter = AB + BC + CD + DA
= ______+ ______+ ______ + ______
= ______ cm

Answer:
Perimeter
= AB + BC + CD + DA
= 40 + 10 + 40 + 10
= 100 cm.

(b) Perimeter = AB + BC + CD + DA 
= ______ + ______ + ______ + ______
= ______

Answer:
Perimeter = AB + BC + CD + DA
= 5 + 5 + 5 + 5
= 20 cm

(c) Perimeter = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= ______ + ______ + ______ + ______ + ______ + ______ + ______ + ______  + ______  + ______ 
= ______ 

Answer:
Perimeter = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= 1 + 3 + 3 + 1 + 3 + 3 + 1 + 3 + 3 + 1 + 3 + 3
= 28 cm.

(d) Perimeter
= AB + BC + CD + DE + EF + FA
= ______ + ______ + ______ + ______ + ______ + ______ 
= ______

Answer:
Perimeter = AB + BC + CD + DE + EF + FA
= 100 + 120 + 90 + 45 + 60 + 80
= 495 m.

(Try These - Page 208)

Question 1.
Find the perimeter of the following rectangles:

Answer:
(ii) Perimeter by adding all the sides
= 0.5 m + 0.25 m + 0.5 m + 0.25 m
= 1.5 m
Perimeter by 2 × (length + breadth)
= 2 × (0.5 m + 0.25 m)
= 2 × 0.75
= 1.5 m

(iii) Perimeter by adding all the sides
= 18 cm + 15 cm + 18 cm + 15 cm
= 66 cm
Perimeter by 2 × (length + breadth)
= 2 × (18 + 15)
= 2 × 33
= 66 cm.

(iv) Perimeter by adding all the sides
= 10.5 cm + 8.5 cm +10.5 cm + 8.5 cm = 38 cm
Perimeter by 2 × (length + breadth)
= 2 × (10.5 + 8.5)
= 2 × 19 
= 38 cm.

(Try These - Page 215)

Question 1.
Draw any circle on a graph sheet. Count the squares and use them to estimate the area of the circular region.
Answer:
Do it yourself.

Question 2.
Trace shapes of leaves, flower petals and other such objects on the graph paper and find their areas.
Answer:
Do it yourself.

(Try These - Page 217)

Question 1. 
Find the area of the floor of your classroom.
Answer:
Let length of classroom = 25 m Breadth = 15 m
Area of classroom = length × breadth
= 25 m × 15 m = 375 m².

Question 2. 
Find the area of any one door in your house.
Answer:
Length of door = 180 cm
Breadth of door = 80 cm
Then, area of door = length × breadth 
= 180 cm × 80 cm = 14400 cm².