RBSE Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2 Textbook Exercise Questions and Answers.

RBSE Class 6 Maths Solutions Chapter 1 Knowing Our Numbers Ex 1.2

Question 1.
A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094,1812,2050 and 2751. Find the total number of tickets sold on all the four days.
Answer:
Number of tickets sold on first day
= 1,094
Number of tickets sold on second day
= 1,812
Number of tickets sold on third day
( =2,050
Number of tickets sold-on fourth day
= 2,751
Total tickets sold = 1,094 + 1,812 + 2,050 + 2,751
= 7,707
Therefore, 7,707 tickets were sold on all the four days.

Question 2. 
Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need? ,
Answer:
Runs to achieve = 10,000
Rims scored = 6,980
Therefore, runs required = 10,000 - 6,980
= 3,020
∴ He needs 3,020 more runs.

Question 3.
In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?
Answer:
Number of votes secured by successful candidate = 5,77,500
Number of votes secured by his nearest rival = 3,48,700
Margin between them
= 5,77,500 - 3,48,700
= 2,28,800
Therefore, the successful candidate won by a margin of 2,28,800 votes.

Question 4.
Kirti book store sold books worth ₹ 2,85,891 in the first week of June and books worth ₹ 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Answer:
Books sold in first week = 2,85,891
Books sold in second week = 4,00,768
Total books sold = 2,85,891 + 4,00,768 = 6,86,659
Since 4,00,768 > 2,85,891
Therefore, sale of second week is greater than that of first week.

Books sold in second week = 4,00,768
Books sold in first week = 2,85,891
More books sold in second week
= 4,00,768 - 2,85,891
= 1,14,877
Therefore, 1,14,877 more books were sold in the second week.

Question 5.
Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2,7,4,3 each only once.
Answer:
Greatest five digit number using digits 6, 2, 7,4, 3 = 76,432
Smallest five digit number using digits 6,2, 7, 4, 3 = 23,467
Difference = 76,432 - 23,467 = 52,965
Therefore, the difference is 52,965.

Question 6.
A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Answer:
Number of screws manufactured in one day = 2,825
Number of days in the month of January (31 days) = 2,825 × 31 = 87,575 
Therefore, the machine produced 87,575 screws in the month of January ,2006.

Question 7.
A merchant had 178,592 with her. She placed an order for purchasing 40 radio sets at 7 1,200 each, how much money will remain with her after the purchase?
Answer:
Cost of one radio = ₹ 1,200
Cost of 40 radios = ₹ 1200 × 40
= ₹ 48,000
Now total money with merchant
= ₹ 78,692
Money spent by her = ₹ 48,000
Leftover money = 78,592 - 48,000 = ₹ 30,592
Therefore, ₹ 30,592 will remain with her after the purchase.

Question 8.
A student multiplied 7236 by 65 instead of multiplying hy 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)
Answer:
First Method:

Difference in answers = 4,70,340 - 4,05,216 = 65,124

Second Method:
Wrong answer was greater than the correct answer by = 7236 × 65 - 7236 × 56 = 7236 (65 - 56)
= 7236 × 9 = 65,124.

Question 9. 
To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: Convert data in cm)
Answer:
Cloth required to stitch one shirt = 2 m 15 cm = 2 × 100 cm + 15 cm = 215 cm
Length of cloth = 40 m = 40 × 100 cm
= 4,000 cm
Number of shirts can be stitched = \(\frac{4000}{215}\) = 18 + 130 cm
Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.

Question 10.
Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
Answer:
The weight of one box= 4 kg 500 g
= 4 × 1000g + 500g = 4,500 g
Maximum weight loaded in van
= 800 kg = 800 × 1000 = 8,00,000 g
Therefore, 177 boxes can be loaded.

Question 11.
The distance between the school and a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.
Answer:
Distance between school to home = 1 km 875 m = 1000 + 875 = 1875 m
Distance covered in one day = 1875 × 2 = 3750 m

Distance covered in six days
= 3750 × 6 = 22500 m = 22 km 500 m 

Question 12.
A vessel has 4 litre and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Answer:
Capacity of curd in a vessel
= 4 litre 500 ml =4 × 1000 + 500 ml
= 4500 ml
Capacity of one glass = 25 ml
Number of glasses that can be filled
= \(\frac{4500}{25}\) = 180
Therefore, 180 glasses can be filled by curd.