RBSE Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2

Rajasthan Board RBSE Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Textbook Exercise Questions and Answers.

RBSE Class 8 Maths Solutions Chapter 4 Practical Geometry Ex 4.2

Question 1.
Construct the following quadrilaterals.
(i) quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
Answer:
First of all we draw a rough sketch of the required quadrilateral and write TK down the dimensions. Clearly, the constructive triangles LIT and LIF.

Steps of Construction:

1. First we draw LI = 4 cm.
2. With L as centre and radius 2.5 cm, we draw an arc.
3. With I as centre and radius 4 cm we draw another arc to cut the previous arc at T.
4. Now we join TL and TI.
5. With L as centre and radius 4.5 cm, we draw an arc.
6. With I as centre and radius 3 cm, we draw another arc to cut the previous arc at F.
7. Now join FI, FL and TF.

Hence we get the required quadrilateral LIFT

(ii) Quadrilateral GOLD
OL = 7.5cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10cm
Answer:
First of all we ot draw a rough sketch of the required quadrilateral and write down its dimensions.
Clearly, the two constructible triangles are LOD and LGD.

Steps of Construction:

1. First we draw LD = 5 cm.
2. With L as centre and radius 7.5 cm, we draw an arc.
3. With D as centre and radius 10 cm, we draw another arc to cut the previous arc at O.
4. Now we join OL and OD.
5. With L as centre and radius 6 cm, we draw an arc.
6. With D as centre and radius 6 cm., We draw an arc to cut the previously draw arc at B.
7. Now we join GD, GL and OG.

Hence we get the x required quadrilateral GOLD.

(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm
Answer:
We know that the diagonals of a rhombus bisect each other at right angles. So we proceed according to the following steps.

Steps of Construction:

1. First we draw DE = 6.5 cm.
2. Now we draw the right bisector XY of DE, meeting DE at O.
3. From O set off ON = \(\frac{1}{2}\)(5.6)cm = 2.8 cm along OY and OB = 2.8 cm along OX.
4. Now we join DN, NE, EB and BD.

Hence BEND is the required rhombus.