Rajasthan Board RBSE Solutions for Class 8 Maths Chapter 12 घातांक और घात Ex 12.1 Textbook Exercise Questions and Answers.
Rajasthan Board RBSE Solutions for Class 8 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 8. Students can also read RBSE Class 8 Maths Important Questions for exam preparation. Students can also go through RBSE Class 8 Maths Notes to understand and remember the concepts easily. Practicing the class 8 maths chapter 6 try these solutions will help students analyse their level of preparation.
प्रश्न 1.
मान ज्ञात कीजिए-
(i) 3-2
हल:
(ii) (-4)-2
हल:
(iii) \(\left(\frac{1}{2}\right)^{-5}\)
हल:
प्रश्न 2.
सरल कीजिए और उत्तर को धनात्मक घातांक के रूप में व्यक्त कीजिए।
(i) (- 4)5 ÷ (- 4)8
हल:
(ii) \(\left(\frac{1}{2^{3}}\right)^{2}\)
हल:
\(\left(\frac{1}{2^{3}}\right)^{2}\) = \(\frac{1}{2^{3 \times 2}}\) = \(\frac{1}{2^{6}}\) उत्तर
(iii) (- 3)4 × \(\left(\frac{5}{3}\right)^{4}\)
हल:
(- 3)4 × \(\left(\frac{5}{3}\right)^{4}\) = (- 1)4 × 34 × \(\frac{5^{4}}{3^{4}}\)
= 1 × 34 - 4 54 = 30 × 54
= 1 × 54 = 54
(iv) (3-7 ÷ 3-10) × 3-5
हल:
(v) 2-3 × (-7)-3
हल:
प्रश्न 3.
मान ज्ञात कीजिए-
(i) (30 + 4-1) × 22
हल:
(ii) (2-1 × 4-1) ÷ 2-2
हल:
(iii) \(\left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}\)
हल:
\(\left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}\) = 22 + 32 + 42
= 4 + 9 + 16 = 29
(iv) (3-1 + 4-1 + 5-1)0
हल:
(3-1 + 4-1 + 5-1)0 = 1 [∵a0 = 1]
(v) \(\left\{\left(\frac{-2}{3}\right)^{-2}\right\}^{2}\)
हल:
\(\left\{\left(\frac{-2}{3}\right)^{-2}\right\}^{2}=\left\{\left(-\frac{3}{2}\right)^{2}\right\}^{2}=\left(\frac{9}{4}\right)^{2}=\frac{81}{16}\)
प्रश्न 4.
मान ज्ञात कीजिए
(i) \(\frac{8^{-1} \times 5^{3}}{2^{-4}}\)
हल:
(ii) (5-1 × 2-1) × 6-1
हल:
प्रश्न 5.
m का मान ज्ञात कीजिए जिसके लिए 5m ÷ 5-3 = 55
हल:
प्रश्न 6.
मान ज्ञात कीजिए
(i) \(\left\{\left(\frac{1}{3}\right)^{-1}-\left(\frac{1}{4}\right)^{-1}\right\}^{-1}\)
हल:
(ii) \(\left(\frac{5}{8}\right)^{-7} \times\left(\frac{8}{5}\right)^{-4}\)
हल:
प्रश्न 7.
सरल कीजिए
(i) \(\frac{25 \times t^{-4}}{5^{-3} \times 10 \times t^{-8}}\) (t ≠ 0)
हल:
(ii) \(\frac{3^{-5} \times 10^{-5} \times 125}{5^{-7} \times 6^{-5}}\)
हल: