RBSE Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3

Rajasthan Board RBSE Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Textbook Exercise Questions and Answers.

RBSE Class 7 Maths Solutions Chapter 10 Practical Geometry Ex 10.3

Question 1.
Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.
Answer:
Steps of consturction :

1. Draw a line segment DE = 5 cm.
2. At D, construct ∠EDX = 90°.
3. From the ray DX, cut off DF = 3 cm.
4. Join EF.

Then, ΔDEF is the required triangle.

Question 2.
Construct an isosceles triangle in which the length of each of its equal sides is 6.5 cm and the angle between them is 110°.
Answer:
Steps of consturction :

1. Draw a line segment AB = 6.5 cm.
2. At B, using a protractor construct ∠ABX = 110°.
3. From the ray BX, cut off BC = 6.5 cm. 
4. Join CA.

Thus, ΔABC is the required isosceles triangle.

Question 3.
Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.
Answer:
Steps of consturction :

1. Draw a line segment BC = 7.5 cm.
2. At C, construct ∠BCA = 60°.
3. From the ray CA, cut off CA = 5 cm.
4. Join AB.

Thus, ΔABC is the required triangle.