RBSE Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.2

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.2 Textbook Exercise Questions and Answers.

RBSE Class 6 Maths Solutions Chapter 7 Fractions Ex 7.2

Question 1.
Draw number lines and locate the points on them:
(a) \(\frac{1}{2}, \frac{1}{4}, \frac{3}{4}, \frac{4}{4}\)
Answer:
To convert all fractions into like fractions, we can write:
\(\frac{1}{2}=\frac{1 \times 2}{2 \times 2}=\frac{2}{4}\)
Now we divide the portion between 0 and 1 into 4 equal parts, then :

Hence, point A denotes \(\frac{1}{4}\), point B denotes \(\frac{1}{2}\) point C denotes \(\frac{3}{4}\) and point D denotes \(\frac{4}{4}\).

(b) \(\frac{1}{8}, \frac{2}{8}, \frac{3}{8}, \frac{7}{8}\)
Answer:
We divide the length between 0 and 1 into 8 equal parts, then:

Hence,points A, B, C and D denotes \(\frac{1}{8}, \frac{2}{8}, \frac{3}{8}\) and \(\frac{7}{8}\) respectively.

(c) \(\frac{2}{5}, \frac{3}{5}, \frac{8}{5}, \frac{4}{5}\)
Answer:
We divide the length between 0 and 1 and between 1 and 2 into five-five equal parts, or show below:

Hence,points A, B, C and D denotes \(\frac{2}{5}, \frac{3}{5}, \frac{4}{5}, \frac{8}{5}\) respectively.

Question 2.
Express the following as mixed fractions:

Answer:
While converting improper fractions into mixed fraction, we write as :
Quotient = \(\frac{\text { Remainder }}{\text { Divisor }}\)

Question 3.
Express the following as improper fractions:
(a) 7\(\frac{3}{4}\)
(b) 5\(\frac{6}{7}\)
(c) 2\(\frac{5}{6}\)
(d) 10\(\frac{3}{5}\)
(e) 9\(\frac{3}{7}\)
(f) 8\(\frac{4}{9}\)
Answer:
We can express a mixed fraction as an improper fraction as :
= \(\frac{(\text { Whole } \times \text { Denominator })+\text { Numerator }}{\text { Denominator }}\)