RBSE Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2 Textbook Exercise Questions and Answers.

RBSE Class 6 Maths Solutions Chapter 2 Whole Numbers Ex 2.2

Question 1.
Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
Answer:
837 + 208 + 363
= (837 + 363) + 208
= 1200 + 208 = 1408

(b) 1962 + 453 + 1538 + 647
Answer:
1962 + 453 + 1538 + 647
= (1962 + 1538) + (453 + 647)
= 3500 + 1100 = 4600

Question 2.
Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
Answer:
2 × 1768 × 50
= (2 × 50) × 1768 = 100 × 1768 = 1,76,800

(b) 4 × 166 × 25
Answer:
4 × 166 × 25
= (4 × 25) × 166 = 100 × 166 = 16,600

(c) 8 × 291 × 125
Answer:
8 × 291 × 125
= (8 × 125) × 291 = 1000 × 291 = 2,91,000

(d) 625 × 279 × 16
Answer:
625 × 279 × 16
= (625 × 16) × 279 = 10000 × 279 = 27,90,000

(e) 285 × 5 × 60
Answer:
285 × 5 × 60
= 285 × (5 × 60)
= 285 × 300 = 85,500

(f) 125 × 40 × 8 × 25
Answer:
125 × 40 × 8 × 25
= (125 × 8) × (40 × 25)
= 1000 × 1000 = 10,00,000

Question 3.
Find the value of the following:
(a) 297 × 17 + 297 × 3
Answer:
297 × 17 + 297 × 3
= 297 (17 + 3)
= 297 × 20 = 5,940

(b) 54279 × 92 + 8 × 54279
Answer:
54279×92+8×54279
= 54279(92 + 8)
= 54279 × 100 = 54,27,900

(c) 81265 × 169 - 81265 × 69
Answer:
81265 × 169 - 81265 × 69
= 81625(169-69)
= 81625 × 100 = 81,62,500

(d) 3845 × 5 × 782 + 769 × 25 × 218
Answer:
3845 × 5 × 782 + 769 × 25 × 218
= 3845 × 5 × 782 + 769 × 5 × 5 × 218 (∵ 25 = 5 ×5)
= 3845 × 5 × 782 + 3845 × 5 × 218 = 3845 × 5 (782 + 218)
= 3845 × 5 × 1000 = 1,92,25,000

Question 4.
Find the product using suitable properties:
(a) 738 × 103
Answer:
738 × 103
= 738 × (100 + 3)
= 738 × 100 + 738 × 3 = 73800 + 2214 = 76,014

(b) 854 × 102
Answer:
854 × 102 = 854 × (100 + 2)
= 854 × 100 + 854 × 2 = 85400 + 1708
= 87,108

(c) 258 × 1008
Answer:
258 × 1008 = 258 × (1000 + 8)
= 258 × 1000 + 258 × 8 = 258000 + 2064 = 2,60,064

(d) 1005 × 168
Answer:
1005 × 168 = (1000 + 5) × 168
= 1000 × 168 + 5 × 168 = 168000 + 840 = 1,68,840

Question 5.
A ta×i driver filled his car petrol tank with 40 litre of petrol on Monday. The next day he filled the tank with 50 litre of petrol. If the petrol cost ₹ 44 per litre, how much did he spend in all on petrol?
Answer:
Given :
Petrol filled on Monday = 40 litre
Petrol filled on Tuesday = 50 litre
Total, filled petrol = 90 litre.
Now, cost of 1 litre petrol = ₹ 44 Cost of 90 litre petrol = 44 × 90
= 44 × (100 - 10)
= 44 × 100 - 44 × 10 = 4,400 - 440 = ₹ 3,960
Therefore, he spent ₹ 3,960 on petrol.

Question 6.
A vendor supplies 32 litre of milk to a hotel in the morning and 68 litre of milk in the evening. If the milk cost ₹ 45 per litre, how much money is due to the vendor per day?
Answer:
Given :
Supply of milk in morning = 32 litre
Supply of milk in evening = 68 litre
Total milk = 32 + 68
= 100 litre
Now, cost of 1 litre milk = ₹ 45
Cost of 100 litre milk = 45 × 100 = 4,500
Therefore, ₹ 4,500 is due to the vender per day.

Question 7.
Match the following:

Answer: