RBSE Solutions for Class 6 Maths Chapter 14 Practical Geometry InText Questions

Rajasthan Board RBSE Solutions for Class 6 Maths Chapter 14 Practical Geometry InText Questions Textbook Exercise Questions and Answers.

RBSE Class 6 Maths Solutions Chapter 14 Practical Geometry InText Questions

(Try These - Page 286)

Question 1.
In step 2 of the construction using ruler and compasses, what would happen if we take the length of radius to be smaller than half the length of \(\overline{A B}\)?
Answer:
In this case, we take the radius smaller than half of the length \(\overline{A B}\). The arcs will not intersect each other at P and Q.

(Try These - Page 290)

Question 1.
How will you construct a 15° angle?
Answer:
Step 1: Construct an angle of 60°.
Step 2: Bisect ∠ABC to get an angle of 30°, i.e. ∠ABD = 30°.
Step 3 : Draw the bisector of ∠ABD, these ∠ABE = ½ (30°) = 15°.

(Try These - Page 291)

Question 1.
How will you construct a 150° angle. 
Answer:

Steps of construction:

1. Draw a line l and mark a point 0 on it.
2. Construct an angle ∠ADC = 120° and ∠AOD = 180°.
3. Draw the bisector of ∠COD.
4. Let OE is the bisector of angle ∠COD, i.e. ∠COE = \(\frac{1}{2}\) = 60° = 30°
   ∠AOE = ∠AOC + ∠COE = 120° + 30° = 150°
5. Therefore, ∠AOE is our required angle of measure 150°.

Question 2.
How will you construct a 45° angle?
Answer:
Steps of construction :

1. Draw a line l and mark a point O on it.
2. Construct an angle of 90° at point O, i.e. ∠POQ = 90°.
3. Draw the angle bisector or of ∠POQ, such' that ∠POQ = i (90°) = 45° or ∠POR = 45°.