RBSE Solutions for Class 5 Maths Chapter 13 Measurement of Length

Rajasthan Board RBSE Solutions for Class 5 Maths Chapter 13 Measurement of Length Textbook Exercise Questions and Answers.

RBSE Class 5 Maths Solutions Chapter 13 Measurement of Length

Practice Work:

Question 1. 
Measurement of the jumping distance by class 5 students in long jump competition is as follows:
Laxmi = 1 meter 20 centimeter
Ankita = 1 meter 10 centimeter
Chanchal = 1 meter 70 centimeter
Gurpreet = 1 meter 50 centimeter
Subani = 1 meter 30 centimeter
(i) Who jumped the maximum distance ? .............. distance ............
(ii) The shortest distance jumped by whom ? ............... distance ..............
Solution: 
(i) Chanchal jumped the maximum distance.
Distance = 1 m 70 cm 

(ii) Ankita jumped shortest distance. 
Distance = 1 m 10 cm.

 

Exercise:

Question 1. 
Convert the units in following questions.
(i) 12 km =    _____  m
(ii) 10\(\frac{1}{2}\) km = _____ m
(iii) 25\(\frac{1}{4}\) m = _____ cm
(iv) 15\(\frac{3}{4}\) m = _____    cm
(v) 4\(\frac{1}{5}\) cm = _____ mm
(vi) 1\(\frac{4}{5}\) cm = _____ mm
Solution: 
(i) 12 km = 12 × 1000 m
= 12000 m

(ii) 10\(\frac{1}{2}\) km = \(\frac{21}{2}\) × 1000 m
= 21 × 500 m = 10500 m

(iii) 25\(\frac{1}{4}\) m = \(\frac{101}{4}\) × 100 cm
= 101 × 25 = 2525 cm

(iv) 15\(\frac{3}{4}\) = \(\frac{63}{4}\) × 100 cm
= 63 × 25 = 1575 cm

(v) 4\(\frac{1}{5}\) cm = \(\frac{21}{5}\) × 10 mm
= 21 × 2 mm = 42 mm

(vi) 1\(\frac{4}{5}\) cm = \(\frac{9}{5}\) × 10 mm
= 9 × 2 mm = 18 mm

  

Question 2.
Convert the units in following, questions.
(i) 120 cm = _____ m
(ii) 2250 m = _____ km
(iii) 50 mm = _____ cm
(iv) 9500 m = _____ km
(v) 150 cm = _____ m
(vi) 175 mm = _____ cm
Solution: 
(i) ∵ 100 cm = 1 m
1 cm = \(\frac{1}{100}\) m
∴ 120 cm = 120 × \(\frac{1}{100}\) m
= \(\frac{6}{5}\) m = 1\(\frac{1}{5}\) m

(ii) ∵ 1 km = 1000 m
1 m = \(\frac{1}{1000}\) km
∴ 2250 m = 2250 × \(\frac{1}{1000}\) km
= \(\frac{225}{100}=\frac{9}{4}=2 \frac{1}{4}\) km.

(iii) ∵ 10 mm = 1 cm
1 mm = \(\frac{1}{10}\) cm
∴ 50 mm = 50 × \(\frac{1}{10}\) = 5 cm

(iv) ∵ 1 km = 1000 m
1 m = \(\frac{1}{1000}\) km
∴ 9500 m = \(\frac{9500}{1000}=\frac{95}{10}\)
= \(\frac{19}{2}=9 \frac{1}{2}\)

(v) ∵ 1 m = 100 cm
1 cm = \(\frac{1}{100}\) m
∴ 150 cm = 150 × \(\frac{1}{100}\)
= \(\frac{15}{10}\)
= \(\frac{3}{2}=1 \frac{1}{2}\)

(vi) ∵ 1 cm = 10 mm
1 mm = \(\frac{1}{10}\) cm
∴ 175 mm = 175 × \(\frac{1}{10}\)
= \(\frac{175}{10}\) cm = \(\frac{35}{2}=17 \frac{1}{2}\) cm

 

Question 3. 
Kavita’s house is, at a distance of 7 kilometer 300 meter from her school. How much distance Kavita has to tavel, while she goes to school and returning back home ?
Solution: 
Kavita goes to school at distance 7 km 300 m and returned back home by same distance.
Thus, distance from home to school = 7 km 300 m
Distance from school home = 7 km 300 m

Thus, required distance is 14 km 600 m.

Question 4. 
A city is 46 kilometer far from Manju’s house. The bus broke down after travelling up to 32 kilometer 600 meter. How much distance she needs to cover ?
Solution: 
Distance of city from Manju’s village = 46 km
Distance covered by bus = 32 km 600 m 
Thus, remaining distance

Thus, required distance is 13 km. 400 m.

 

Important Questions:

Multiple Choice Questions:

Question 1. 
Meter in 100 cm will be:
(a) 2 m 
(b) 1 m
(c) 3 m 
(d) 0 m
Solution:
(b) 1 m

Question 2. 
Millimeter in 5 m will be:
(a) 500 
(b) 400 
(c) 5000 
(d) 100
Solution:
(a) 500 

Question 3. 
Milimeter in 1 centimether are:
(a) 20 
(b) 15 
(c) 10 
(d) 50
Solution:
(c) 10 

 

Question 4. 
In measurement of long distance in convenient way we used:
(a) meter scale 
(b) iron rod
(c) wooden scale 
(d) tape
Solution:
(d) tape

Question 5. 
It is used to measure length:
(a) weight 
(b) litre
(c) tape 
(d) wooden rod
Solution:
(c) tape 

Question 6. 
Unit of measure short distance
(a) mm/cm 
(b) kg/gm
(c) t /mi 
(d) None of these
Solution:
(a) mm/cm 

Question 7. 
Ishu’s height is 123 cm and Kriti’s height is 129 cm.
Difference between their heights will be :
(a) 5 cm
(b) 4 cm
(c) 6 cm
(d) 7 cm
Solution:
(c) 6 cm

 

Very Short/Short Answer Type Questions:

Question 1. 
Fill in the blanks:
(a) 1 m = _____ cm
(b) 15 km = _____ m
(c) 1000 m    = _____ km
(d) 900 cm = _____ m
(e) 100 cm    = _____ m
(f) 10 m = _____ cm
(g) 2000 m = _____ km
Solution: 
(a) 100
(b) 15000
(c) 1
(d) 9
(e) 1
(f) 1000
(g) 2. 

 

Question 2. 
By estimating length, fill in the blanks:
1. Length of black-board = ....................
2. Length of carpet = ....................
3. Length of book = ....................
4. Length of table = ....................
5. Length of room = ....................
6. Width of window = ....................
7. Width of carpet = ....................
8. Width of table = ....................
9. Width of room = ....................
10. Width of doo = .................... 
Solution: 
1. 80 cm
2. 2 m 50 cm
3. 22 cm
4. 75 cm
5. 6 m 20 cm
6. 95 cm
7. 35 cm
8. 50 cm
9. 4 m 10 cm
10. 1 m 30 cm.

 

Question 3. 
Following are the figures of length of pencils of Mahesh, Greg, Sumna and Riana before start drawing and after drawing by seeing figures, solve the following questions.

Solution:

Name	Length of Pencil before Drawing	Length of Pencil after Drawing
Riana	5 cm 6 mm	3 cm 00 mm
Summa	6 cm 2 mm	4 cm 3 mm
Greg	7 cm 3 mm	6 cm 2 mm
Mahesh	8 cm 4 mm	6 cm 5 mm

 

Question 4. 
The distance from Delhi to Jaipur is 275 km and from Jaipur to Aimer is 131 km, then how much distane between Delhi and Aimer?
Solution: 
Distance from Delhi to Jaipur + from Jaipur to Ajmer
275 km + 131 km = 406 km

Question 5. 
Shyam’s house is at 800 metre for from school and Ramesh’s house is at 600 metre for from school and school is situated in the mid of Shyam and Ramesh houses. Then find how much distance from house to Ramesh house?
Soution: 
Distance between Shyam’s house and school = 800 m
Distance between Ramesh’s house and school = 600 m
Thus, distance between Shyam and
Ramesh houses = 800 + 600 m = 1400m

Question 6. 
Puneet covers 2 kin 500 m distance to reach school from his house then how much distance he will covered in two ways (go and return)?
Solution: 
Distance travelled in going = 2 km 500m
Distance travelled in return = 2 km 500 m
Thus, total distance 4 km + 1000 m = 5 km

Required distance = 5 km

 
 
Question 7. 
Find, who is longest jump. 
Chancal - 1 m 10 cm (110cm) 
Shaheen - 1 m 40 cm (140 cm)
Vidhya - 1 m 70 cm (170 cm) 
Shaheen - 1 m 30 cm (130 cm)
Who’s longest jump ?    
Solution: 
Longest jump by Vidhya (170 cm).