RBSE Solutions for Class 5 Maths Chapter 12 Weight

Rajasthan Board RBSE Solutions for Class 5 Maths Chapter 12 Weight Textbook Exercise Questions and Answers.

RBSE Class 5 Maths Solutions Chapter 12 Weight

Practice Work:

Question 1. 
Convert 5 kg in gin.
Solution:
4 kg = gm
4 kg = 1 kg + 1 kg + 1 kg + 1 kg
4 kg = 1 kg + 1 kg + 1 kg + 1 kg
∵ 4 kg = 1000 gm + 1000 gm + 1000 gm + 1000 gm = 4000 gm 

Question 2. 
Convert 3000 gm in kg.
Solution: 
3000 gm = 3 kg
∵ 3000 gm = 1000 gm + 1000 gm + 1000 gm 
= 1 kg + 1 kg + 1 kg = 3 kg

 

Question 3. 
Fill in the blanks :
(i) 200 gm = ______ kg
(ii) 400 gm = ______ kg
(iii) 1250 gm = ______ kg
Solution: 

Question 4. 
Convert 1\(\frac{1}{4}\) kg into gm.
Solution: 
1\(\frac{1}{4}\) kg = \(\frac{5}{4}\) × 1000 gm
= 5 × 250 gm 
= 1250 gm

Question 5. 
Convert 1\(\frac{3}{4}\) kg into gm.
Solution: 
1\(\frac{3}{4}\) kg = \(\frac{7}{4}\) × 1000 gm
= 7 × 250 gm 
= 1750 gm

Generally following weights are used: 5 kg, 2kg, 1 kg, 500 gm, 200 gm, 100 gm, 500 gm.

 

Question 6. 
Divide weight of the following with the help of these weighing units:
Solution:

Question 7. 
Ramesh has a weight of 5 kg and 500 grams each. He has to weigh 4 kg 500 gm of sugar. Looking at the scales carefully, tell whether the quantity of sugar kept in the bag will be 4 kg 400 grams or not? 

Solution:
Since the bag and weight of 500 grams together make 5 kg equal to the load. Therefore, 500 grams of sugar will be less than 5 kg in the bag, that is, weight of sugar = 5 kg - 500 grams = 4 kg 500 gm.

 

Question 8. 
(1) Weight out 300 gm with the help of 500 gin and 200 gm weighting units.
(2) Weigh out 700 gm with the help of 1 kg, 200 gm and 100 gin iron weight units.
Solution: 
(1) Place 500 gm weighing unit at one side and 200 gm weighting unit + item on other side, so item weight will be 300 gm.
(2) Place 1 kg weighing unit at one side and weighing unit of 200 and 100 gm + item on other side so item weight will be 700 gm.

Exercise:

Question 1. 
Reena purchases 1 kg 400 gm tomatoe, 750 gm chilli and 2 kg 600 gm potatoe from market and put in her bag. What is the total weight of her bag?
Solution: 

= 3 kg + 1 kg + 750 gm 
= 4 kg 750 gm
Thus, total weight of bag is 4 kg 750 gm.

 

Question 2. 
Manoj bought 10 kg bag of sugar from the market. While returning home due to a hole in the bag, some sugar is scattered out through the hole and 8 kg 750 gm sugar remained. Find out the weight of scattered quantity of sugar.
Solution: 
(∵ 1 kg = 1000 gm)

Thus, 1 kg 250 gm sugar was scattered.
 
Question 3. 
Sheela is having a packet of 5 kg 470 gm and a box of 3 kg 690 gm. Weight of the packet is how much more than that of the box?
Solution: 
(∵ 1 kg = 1000 gm)

Thus, weight of packet is 1 kg 780 kg more than that of box.

 

Question 4.
A shopkeeper sells 250 gm packet of spices by grinding them from 6 kg of spices. Find out the num¬ber of thus formed packets if 4 pack¬ets of 250 gm are prepared from 1 kg of spices.
Solution: 
By grinding 6 kg spicies, we find No. of 250 gm packets as
∵ No. of 250 gm packets in 1 kg = 4 
∴ No. of 250 gm packets in 6 kg = 6 × 4 = 24
Required no. of packets = 24

Question 5. 
If 150 gm of wheat and 100 gm of rice per child is required for the mid day meal, then how much wheat and rice is needed for 60 children?
Solution: 
Per child wheat required = 150 gm
Per child rice Required = 100 gm 
For 60 children required wheat = (60 × 150) gm = 9000 gm
= \(\frac{9000}{1000}\) kg = 9 kg
For 60 children required rice = (60 × 100) gm = 6000 gm
= \(\frac{6000}{1000}\) kg = 6 kg
Thus, 9 kg wheat and 6 kg rice will required. 

 

Question 6. 
Savita bought 2 kg of cabbage, 4 kg of cucumber, 3 kg 700 gm of yam and 2 kg 900 gm of other vegetables from market. Find out the total weight of her bag.
Solution: 

Total weight in Savita’s bag will be 12 kg 600gm.

Question 7. 
Harish brought 2 kg 500 gm turmeric, 5 kg 200 gm chili, 4 kg 700 gm coriander and 10 kg salt from grain market. What is the total weight of all goods?
Solution:

Thus, total weight of all goods is 21 kg + 1000 gm + 400 gm = 22 kg 400 gm.

 

Question 8. 
Find out:
(i) 3\(\frac{1}{2}\) kg = ..............gm
(ii) 3\(\frac{2}{5}\) kg = ................. gm
(iii) 4\(\frac{3}{4}\) kg = ................ gm
(iv) 2\(\frac{1}{5}\) kg = ............... gm
Solution:
(i) 3\(\frac{1}{2}\) kg = \(\frac{7}{2}\) × 1000 gm
= 7 × 500 gm = 3500 gm

(ii) 3\(\frac{2}{5}\) kg = \(\frac{17}{5}\) × 1000 gm
= 17 × 200 gm = 3400 gm

(iii) 4\(\frac{3}{4}\) kg = \(\frac{19}{4}\) × 1000 gm
= 19 × 250 gm = 4750 gm

(iv) 2\(\frac{1}{5}\) kg = \(\frac{11}{5}\) × 1000 gm
= 11 × 200 gm = 2200 gm

Question 9. 
Find out:
(i) 1500 gm = ............. kg
(ii) 2250 gm = ................ kg
(iii) 100 gm = ................ kg
(iv) 4750 gm = ................ kg
Solution: 
(i) 1500 gm = 1500 × \(\frac{1}{1000}\) kg
= \(\frac{1500}{1000} \mathrm{~kg}=\frac{3}{2}=1 \frac{1}{2}\) kg

(ii) 2250gm = 2250 × \(\frac{1}{1000}\) kg
= \(\frac{2250}{1000} \mathrm{~kg}=\frac{9}{4}=2 \frac{1}{4}\) kg

(iii) 100 gm = 100 × \(\frac{1}{1000}\) = \(\frac{1}{10}\) kg

(iv) 4750 gm = 4750 × \(\frac{1}{1000}\) kg
= \(\frac{4750}{1000}=\frac{475}{100}=\frac{95}{20}=\frac{19}{4}=4 \frac{3}{4}\) kg

 

Question 10.
Find true and false statement:
(i) 1 gram is 100th part of 1 kilo gram. 
Solution:
False

(ii) Multiply by 1000 to convert kilogram unit into gram unit.
Solution:
True

(iii) 4 packets of 250 gm salt can be formed from 1 kg of salt.
Solution:
True

(iv) It the size of wooden stick and iron weight unit are equal, their weights are also equal.
Solution:  
False

 

Important Questions:

Multiple Choice Questions:

Question 1.    
How many grams in 1 kg ?
(a) 10 gm    
(b) 1 gm
(c) 100 gm    
(d) 1000 gm
Solution:
(d) 1000 gm

Question 2.    
What will be the total weight on adding 3 kg and 750 gm ?
(a) 3750 gm 
(b) 3570 gm 
(c) 3150 gm 
(d) 6250 gm
Solution:
(a) 3750 gm 

Question 3.    
How many kilograms in 2000 gm ? 
(a) 2000 kg 
(b) 200 kg
(c) 2 kg    
(d) 20 kg
Solution:
(c) 2 kg

 

Question 4.    
Grams in 5 kg are :
(a) 500 gm 
(b) 5000 gm 
(c) 15 gm    
(d) 50 gm
Question 
Solution:
(b) 5000 gm 

Question 5.    
By adding 22 kg and 19 kg, total weight will be :
(a) 41 kg    
(b) 39 kg
(c) 40 kg    
(d) 42 kg
Solution:
(a) 41 kg  

   

Very Short Answer Type Questions:

Question 1. 
Fill in the blanks :
Question 1.    
2500 gm = ............. kg.
Solution:
2.5 kg,

Question 2
1650 gm =    .............  kg
Solution:
1.650 kg

Question 3. 
475 gm = .............  kg
Solution: 
0.475 kg 

 

Question 2.
Divide 5 kg 950 gm by weight¬ing units.
Solution: 
5 kg + 500 gm + 200 gm + 200 gm + 50 gm

Question 3. 
Can you weigh 700 gm using two weighing units? How? Whereas 500 gm weighing unit is not used.
Solution: 
Yes, using 1 kg 200 gm and 100 gm of weighing units as -
Put 1 kg weighing unit one side and 700 gm, 200 gm and 100 gm weighing units on other side.
 
Question 4. 
Write True or False :
1. 6\(\frac{1}{2}\) kg is same as 6500.
Solution:
True

2. To measure 2.450 kg 3 or 4 weights can be used.
Solution:
True

3. If weighing units from 50 gm to 10 kg are added, then their sum will be 18 kg 850 gm.
Solution:
True

4. In 120 gm weight is \(\frac{1}{50}\) kg.
Solution: 
False.

 

Short Answer Type Questions:

Question 1. 
If 500 gm flour to required for 1 meal, then how many mean can be prepared by 2 kg flour?
Solution: 
1 kg = 1000 gm 
∴ \(\frac{1}{2}\) kg = 500 gm
By \(\frac{1}{2}\) kg (500 gm) flour = 1 time
By \(\frac{1}{2}\) + \(\frac{1}{2}\) (1 kg) flour = 2 times
Then by 2 kg flour, meal prepared = 2 × 2 = 4 tim
Thus, using 2 kg flour, 4 times meal pre-pared.

Question 2. 
A animal keeper had got 63 kg 250 gm wool from sheep and 32 kg 675 gm wool from camels, find how much wool he had got?
Solution: 
Animal keeper got wool from sheep = 63 kg 250 gm
Wool got by camel = 32 kg 675 gm
Thus, total wool he got = 95 kg 925 gm

Thus, animal keeper had got 95 kg 925 gm wool.

 

Question 3. 
Convert givem measure in kg. 
(a) 70 gm 
(b) 999 gm 
(c) 10 kg 800 gm 70
Solution: 
(a) 70 gm = \(\frac{70}{1000}\) = 0.070 kg
(b) 999 gm = \(\frac{999}{1000}\) kg = 0.999 kg
(c) 10 kg 800 gm
= 10 kg + 800 gm = 10 kg + \(\frac{800}{1000}\) kg
= 10 kg + 0.8 kg = 10.8 kg

Question 4. 
Naveen farmer bought 70 kg 500 gm grass for his animals, 53 kg 250 gm grass has eaten by animals. How much grass left?
Solution: 
Naveen farmer purchased kg gm gass =    70 kg 500 gm
Grass eaten by animals = 53 kg 250 gm
Grass left with him = 17 kg 250 gm

Thus, 17 kg 250 gm grass left with him.
 
Question 5. 
Suresh bought a sack of sugar of 95 kg 500 gm at his shop. Out of this, he sold 78 kg 250 gm sugar, then find how many sugar left with him?
Solution: 
Sugar bought by Suresh =    95 kg 500 gm
Sugar sold = 78 kg 250 gm
Sugar left with him = 17 kg 250 gm

 

Question 6. 
Primary school Kota had got 225 kg wheat for nutrition out of this, 207 kg wheat has distributed to students. Find how many wheat left?
Solution: 
Wheat obtained in school Kota = 225 kg
Wheat distributed to students = 207 kg
Thus, remaining wheat = 18 kg