RBSE Solutions for Class 5 Maths Chapter 11 Time

Rajasthan Board RBSE Solutions for Class 5 Maths Chapter 11 Time Textbook Exercise Questions and Answers.

RBSE Class 5 Maths Solutions Chapter 11 Time

Practice 11.1

Class 5 Maths Chapter 11 Time Question 1.
Convert the following hours into minutes.

(1) 1\(\frac{1}{4}\) hour = _______ minutes
(2) 2\(\frac{1}{2}\) hour    = _______ minutes
(3) 5\(\frac{3}{4}\) hour    = _______ minutes
(4) 3\(\frac{1}{5}\) hour    = _______ minutes
Solution: 
(1) 1\(\frac{1}{4}\) hour = \(\frac{5}{4}\) × 60 minutes
= 5 × 15 minutes 
= 75 minutes

(2) 2\(\frac{1}{2}\) hour = \(\frac{5}{2}\) × 60 minutes
= 5 × 30 min. = 150 min.

(3) 5\(\frac{3}{4}\) hour = \(\frac{23}{4}\) × 60 min.
= 23 × 15 min. = 345 min.

(4) 3\(\frac{1}{5}\) hour = \(\frac{16}{5}\) × 60 min.
= 16 × 12 min. = 192 min.

 

Practice 11.2

Class 5 Maths Time Chapter Question 1. 
Convert the time units of following questions:
1. 20 min. = _______ seconds
2. 6\(\frac{1}{2}\) min. = _______ seconds
3. 15\(\frac{1}{4}\) min. = _______ seconds
4. 4 hour = _______ seconds
5. 2\(\frac{3}{4}\) hour = _______ seconds
Solution: 
1. 20 min. = 20 × 60 sec.
= 1200 sec

2. 6\(\frac{1}{2}\) min. = \(\frac{13}{2}\) × 60 sec
= 13 × 30 = 390 sec.

3. 15\(\frac{1}{4}\) min. = \(\frac{61}{4}\) × 60 sec
= 61 × 15 sec = 915 sec.

4. 4 hrs. = 4 × 3600 sec.
= 14400 sec.

5. 2\(\frac{3}{4}\) hrs. = \(\frac{11}{4}\) × 3600 sec.
= 11 × 900 sec.
= 9900 sec.

Exercise:

Time Chapter Class 5 Question 1.
Convert the time units of following questions.
(i) 10\(\frac{3}{5}\) hr. = _______ min.
(ii) 2\(\frac{1}{4}\) hr. = _______ sec.
(iii) \(\frac{1}{5}\) min. = _______ sec.
(iv) 1\(\frac{2}{3}\) min. = _______ sec.
Solution:
(i) 10\(\frac{3}{5}\) hr. = \(\frac{53}{5}\) × 60 min.
= 53 × 12 min. = 636 min.

(ii) 2\(\frac{1}{4}\) hr. = \(\frac{9}{4}\) × 3600 sec.
= 9 × 900 sec. = 8100 sec.

(iii) \(\frac{1}{5}\) min. = \(\frac{1}{5}\) × 60 sec. = 12 sec.

(iv) 1\(\frac{2}{3}\) mm. = \(\frac{5}{3}\) × 60 sec.
= 5 × 20 sec. = 100 sec.

Exercise 11.2 Class 5 Question 2. 
Add:
(i) 2 hrs. 42 min. and 4 hrs. 10 min.
(ii) 10 min. 50 sec. and 8 min. 20 sec.
(iii) 4 hrs. 25 min. 45 sec. and 7 hrs. 12 min. 5 sec.
(iv) 9 hrs. 36 min. 2 sec. and 5 hrs. 40 min. 52 sec.
Solution: 
(i)

(ii)

= 18 min. + 60 sec. + 10 sec. 
= 18 min. + 1 min. + 10 sec. 
= 19 min. 10 sec.

(iii)

(iv)

= 14 hrs. (60 + 16) min. 54 sec.
= 15 hrs. 16 min. 54 sec.

Time For Class 5 Question 3. 
Subtract:
(i) 9 hours 32 minutes from 12 hours 18 minutes
(ii) 25 minutes 49 seconds from 29 minutes 39 seconds
(iii) 7 hours 35 minutes from 14 hours 8 minutes
(iv) 10 hours 50 minutes from 20 hours 40 minutes
Solution: 
(i) 12 hrs. 18 min.
- 9 hrs. 32 min.
Since, 32 min. cannot subtract from 18 min. So, add 18 min. to 60 min. by taking 1 hr from 12 hrs, (= 60 min.) in 18 min. 
Then, 60 + 18 = 78 min.
Thus,    

(ii) 29 min. 39 sec.
- 25 min. 49 sec.
Since, 49 sec. cannot subtract from 39 sec.
So, take 1 mm from 29 min (= 60 sec) and add in 39 sec. then.
60 + 39 = 99 sec.
Thus,

(iii) 14 hrs. 8 min.
- 7 hrs. 35 min.
Since, 35 min. cannot subtract from 8 min. So that 1 hr from 14 hrs. (= 60 min.) and add in 8 minutes. 
Then, 60 + 8 = 68 minutes
Thus,

(iv) 20 hrs. 40 min.
- 10 hrs. 50 min.
Since, 50 minutes cannot subtract from 40 minutes. So, take 1 hr (=60 min.) from 20 hrs. and add in 40 min.
Then

Class 5 Maths Chapter 11 Question Answer Question 4. 
Yogesh has been studying for 5 hours 30 minutes in school and 3 hours 45 minutes at home. How much time is he studying per day?
Solution: 
Time passed in school = 5 hrs. 30 min. 
Time passed in study = 3 hrs. 45 min.
Total time 

= 8 hrs. (60 + 15) min.
= (8 + 1) hrs. 15 min.
= 9 hrs. 15 min.
 
Time Math For Class 5 Question 5. 
The distance between Dholpur and Bharatpur is 90 km. Rakesh takes just 2 hours 12 minutes to complete this distance by car and Firoj takes 3 hours 8 minutes by motorcycle. Find out the extra time taken by Firoj as compared to Rakesh.
Solution:
From question, it hr. is clear that Firoz had taken more time.

Thus, Firoz had 56 mine more than Rakesh. 

Time Chapter In Maths For Class 5 Question 6. 
Identify true and false :
(i) Divide by 60 to convert minute into seconds
(ii) 3600 seconds are there in one hour.
(iii) Time taken by minute hand of a clock to cover 60 small parts. It is equal to the time taken by, hour hand to complete the distance of a big part.
(iv) Half hour is equal to 15 minutes. 
Solution:
(i) False 
(ii) True 
(iii) True 
(iv) False.

Important Questions:

Multiple Choice Questions:

Question 1.    
Mid night 12 : 00 clock in railway time is written as :
(a) 12.00    
(b) 24.00
(c) 00.00    
(d) None of these
Solution:
(c) 00.00

Question 2.    
Minutes is 120 sec. will be :
(a) 1 min.    
(b) 2 min.
(c) 3 min.    
(d) 4 min.
Solution:
(b) 2 min.

Question 3.    
Number of minutes in one hour are :
(a) 12    
(b) 36    
(c) 24    
(d) 60
Solution:
(d) 60

Question 4.    
Number of seconds in 1 minute are :
(a) 360    
(b) 36
(c) 60    
(d) 24
Solution:
(c) 60

Question 5.    
Number of hours in 1 day are :
(a) 60    
(b) 24    
(c) 36    
(d) 12 
Solution:
(b) 24    

Question 6.    
At 6’ O’ clock, minute needle will be :
(a) at 6 
(b) at 9 
(c) at 12 
(d) at 8 
Solution:
(c) at 12 

Very Short Answer Type Questions:

Question 1. 
Write the answer of the following questions.
(i) How many minutes are there in 1 hour?
(ii) Longer needle of clock, what tells?
(iii) What time of interval in the school?
(iv) How many needles are there in a clock?
Solution:
(i) 60 min.
(ii) Minutes 
(iii) Write according to time table of your school
(iv) 3 needles.

Question 2. 
Fill in the blanks :
(a) 310 min. = _____ hrs _____ min.
(b) 2 hrs. 15 min. = _____ min.
(c) 645 sec. = 645 ÷ _____ min. =     _____ min. _____ sec.
(d) 18 min. = 18 x    _____ sec. = _____ sec
Solution:
(a) 310 min. = hrs.
= 5 hrs. 10 min.

(b) 2 hrs. 15 min.= 2 hrs. + 15 min.
= 2 × 60 min. + 15 min.
= 120 + 15 = 135 min.

(c) 645 sec. = 645 ÷ 60 min.
= 10 min. 45 sec.

(d)    18 min. = 18 × 60 sec.
= 1080 sec.

Question 3. 
Solve:

Solution:

 
∴ 60 min. = 1 h.    
∴ 1 h. = 60 min.

Question 4. 
Suraj daily walks 1 hr. 10 min. in the morning. If he walk in evening for same direction, then what will be his total walking time daily?
Solution: 
Walking time in morning = 1 hr. 10 min.  and same duration for walking in evening.
Total time = 1 hr. 10 min. + 1 hr. 10 min.
= 2 hrs. 20 min.

Question 5. 
What will be the time difference from 11.00 am to 11.30 pm 
Solution: 
Time duration between 11.0 am to 12.00 noon = 1 hour 
Time duration between 12.0 noon = 11 hours 30 minutes 
Time duration between 11.0 am to 11.30 pm = 1 hours + 11 hours 30 minutes = 12 hours 30 minutes 

Question 6. 
What will be the time difference between 4.00 am to 2.00 pm?
Solution: 
Time duration between 4.00 am to 12.00 noon = 8 hours 
Time duration between 12.00 noon to 2.00 pm = 2 hours 
∴ Time duration between 4.00 am to 2.00 pm = (8 + 2) = 10 hours 

Question 7. 
Jaffer daily walks 1 hr 30 min. in morning and 1 hr. 15 min. in evening. What is his total walking time daily?    hrs. min
Solution: 
Jaffar walks in morning = 1 hrs. 30 min.
And walks in evening = 1 hrs. 15 min.

Thus, total walking time 2 hrs. 45 min.

Question 8. 
Deva farmer had watered his field 4 hrs. 15 min. in two days. If first day he had watered his field 2 hrs. 30 min., then how much time was taken by Deva farmer to watered his field on second day?
Solution:
(∴ 1 hr. = 60 min.)
In two days, Deva watered his field = 4 hrs. 15 min.
On first days, Deva watered his field = 2 hrs. 30 min.
On second days, Deva watered his field = 1 hrs. 45 min.

Thus, Deva farmer watered 1 hrs. 45 min. on second day.
 
Question 9.
A train starts from Chittod at 13.0    and arrives Jaipur at 23.00. Find travelling time by train.
Solution:    
hrs. min.
Arrival time = 23 hrs 30 min.
Travelling start at =    13 hrs 00 min.
Total time in travelling 10 hrs 30 min.

Thus, travelling time by train will be 10 hrs. 30 min.

Question 10. 
Suresh starts his journey from Jabalpur at 5.00 am by Satpuda Express and arrives Nainpur at 9.05 am Find total travelling time.
Solution: 
Satpuda Express    starts    from Jabalpur at 5.00 a.m. and arrives Nainpur station at 9.05 am.
Arrival time at Nainpur = 9 hrs 05 min. 
Starts from Jabalpur = 5 hrs 00 min. 
Travelling time    4 hrs 05 min. 

Required time = 4 hrs. 05 min.