RBSE Class 8 Maths Notes Chapter 11 Mensuration

These comprehensive RBSE Class 8 Maths Notes Chapter 11 Mensuration will give a brief overview of all the concepts.

Rajasthan Board RBSE Solutions for Class 8 Maths in Hindi Medium & English Medium are part of RBSE Solutions for Class 8. Students can also read RBSE Class 8 Maths Important Questions for exam preparation. Students can also go through RBSE Class 8 Maths Notes to understand and remember the concepts easily. Practicing the class 8 maths chapter 6 try these solutions will help students analyse their level of preparation.

RBSE Class 8 Maths Chapter 11 Notes Mensuration

→ Area of a trapezium = \(\frac{1}{2}\) × (Sum of parallel sides) × height
= \(\frac{1}{2}\) × (Sum of parallel sides) × perpendicular distance between them.

→ Area of a rhombus = half the product of its diagonals.

→ Total surface area of a solid is the sum of the areas of its faces.

→ Total surface area of cuboid = 2(lb + bh + hl)
Where l = length, b = width/breadth, h = height

→ The lateral surface area of cuboid = 2(l + b)h
= Perimeter of base × height.

→ Total surface area of a cube = 6l2, where l = edge (or side)

RBSE Class 8 Maths Notes Chapter 11 Mensuration

→ Lateral surface area of cube = 4(side)2 = 4l2

→ Total surface area of a cylinder = 2πr (r + h)

→ Curved surface area of a cylinder = 2πrh

→ Amount of region occupied by a solid is called its volume.

→ Volume of cuboid = Length × Breadth × Height
= l × b × h

→ Volume of cube = (side)3 = a3

→ Volume of a right circular cylinder = (Area of base) × height
= πr2 × h = πr2h

  • 1 cm3 = 1 mL
  • 1 L = 1000 cm3
  • 1m3 = 1000 L
  • 1 m2 = cm2
  • 1 km2 = 106 m2 = 100 hectares
  • 1 hectare = 100 acres = 10000 m2
Prasanna
Last Updated on June 1, 2022, 2:49 p.m.
Published June 1, 2022