RBSE Class 7 Maths Important Questions Chapter 7 Congruence of Triangles

Rajasthan Board RBSE Class 7 Maths Important Questions Chapter 7 Congruence of Triangles Important Questions and Answers.

RBSE Class 7 Maths Chapter 7 Important Questions Congruence of Triangles

Multiple Choice Questions

Question 1.
If ΔABC = ΔPQR, then \(\overline{A B}\) corresponds to :
(a) PQ
(b) PR
(c) QR
(d) None of these
Answer:
(a) PQ

Question 2.
‘Under a given correspondence, two triangles are congruent if the three sides of the one are equal to the three corresponding sides of the other.’
The above is known as :
(a) SSS congruence of two triangles
(b) SAS congruence of two triangles
(c) ASA congruence of two triangles
(d) RHS congruence of two right-angled tringles.
Answer:
(a) SSS congruence of two triangles

Question 3.
‘Under a given correspondence, two triangles are congruent if two angles and the side included between them in one of the triangles are equal to the corresponding angles and the side included between them of the other triangle.’
The above is known as :
(a) SSS congruence of two triangles
(b) SAS congruence of two triangles
(c) ASA congruence of two triangles
(d) RHS congruence of two right-angled triangles.
Answer:
(c) ASA congruence of two triangles

Question 4.
Complete the congruence statement ABCA ≅ ?

(a) ΔBTA
(b) ΔBAT
(c) ΔABT
(d) ΔATB
Answer:
(a) ΔBTA

Question 5.
Complete the congruence statement ΔQRSS ?

(a) ΔTPQ
(b) ΔTQP
(c) ΔQTP
(d) ΔQPT
Answer:
(a) ΔTPQ
 
Fill in the Blanks

Question 1.
If ΔABC = ΔPQR, then ∠A corresponds to ____________
Answer:
∠P

Question 2.
Two angles are congruent if they have ____________
Answer:
same measures

Question 3.
Number of elements of a triangle is ____________
Answer:
6

Question 4.
In ΔPQR, the included sided between ∠P and ∠Q is ____________
Answer:
PQ

Question 5.
Two plane figures are congruent if they have ____________
Answer:
same shape and size

State whether True or False

Question 1.
Two squares are congruent, if they have same length.
Answer:
True

Question 2.
Two circles are congruent, if they have same area.
Answer:
False

Question 3.
RHS congruence condition is applicable to right-angled triangles.
Answer:
True

Question 4.
Two line segments are congruent if they have same length. 
Answer:
True

Very Short Answer Type Questions

Question 1.
Which are congruent angles?

Answer:
∠DOB ≅ ∠AOC and ∠DOA = ∠BOC. 

Question 2.
In ΔABC and ΔQRP, BC = RP. What addition information is required to prove the congruency of ΔABC and ΔQRP by ASA congruence criterion.
Answer:
For ASA congruence criterion
BC = RP (given)
Other information required is
∠B = ∠R and ∠C = ∠P

Question 3.
What is the angle between side \(\overline{D E}\) and \(\overline{E F}\) of ΔDEF?
Answer:
Required angle is ∠DEF.

Question 4.
In ΔPQR and ΔFED, PQ = FE and RP = DF. What addition information is required to prove the congruency of ΔPQR and ΔFED by SAS criterion.
Answer:
To prove the congruency of ΔPQR and ΔFED by SAS criterion, we required ∠P = ∠F

Question 5.
What is the side betweem ∠M and ∠N of ΔMNP?
Answer:
The side between ∠M and ∠N of ΔMNP is MN.

Short Answer Type Questions

Question 1.
In figure, AD bisects A and AD ⊥ BC.
(i) Is ΔADB ≅ ΔADC?
(ii) State the three pairs of matching parts you have used in (i).
(iii) Is it true say that BD = DC?

Answer:
(i) Yes, ΔADB ≅ ΔADC, by ASA criterion of congruency.
(ii) We have used ∠BAD = ∠CAD,
∠ADB = ∠ADC = 90° 
Since, AD ⊥ BC and AD = DA (Common side)

(iii) Yes, BD = DC 
since, ΔADB ≅ ΔADC.

Question 2.
In figure, AO = OB and ∠A = ∠B. 
(i) Is ΔAOC ≅ ΔBOD
(ii) State the matching pair you have used, which is not given in the question.
(iii) Is true to say that ∠ACO = ∠BDO?

Answer:
(ii) We have used
∠OAC = ∠OBD
AO = OB
Also, ∠AOC = ∠BOD
(Opposite angles on same vertex or vertically opposite angles) 

(i) By ASA congruent rule,
ΔAOC ≅ ΔBOD

(iii) Yes, ∠AOC ≅ ∠BOD
(By corresponding parts of congruent triangles)

Question 3.
In figure, AX bisects ∠B AC as well as ∠BDC. State the three facts needed to ensure that ΔACD = ΔABD.

Answer:
As per the given,
∠CAD = ∠BAD and ∠CDA = ∠BDA (Because AX bisects ∠BAC) AD = DA (Common)
Therefore, by ASA congruent rule,
ΔACD ≅ ΔABD.