RBSE Class 6 Maths Important Questions Chapter 10 Mensuration

Rajasthan Board RBSE Class 6 Maths Important Questions Chapter 10 Mensuration Important Questions and Answers.

RBSE Class 6 Maths Chapter 10 Important Questions Mensuration

Multiple Choice Questions

Question 1.
If length of a rectangle is doubled, keeping the breadth same then area of rectangle:
(a) is doubled
(b) increases by 2 units
(c) becomes 4 times
(d) remains the same
Answer:
(a) is doubled

Question 2.
The area of square with perimeter 44 cm:
(a) 88 sq. cm
(b) 44 × 44 sq. cm
(c) 121 sq. cm
(d) 4 × 44 sq. cm
Answer:
(c) 121 sq. cm

Question 3.
The sides of a rectangle are in the ratio 5 : 4. If its perimeter is 72 cm, then its length is:
(a) 40 cm
(b) 20 cm
(c) 30 cm
(d) 60 cm
Answer:
(b) 20 cm

Question 4.
The cost of fencing a rectangular field 34 m long and 18 m wide at ₹ 2.25 per meter is
(a) ₹ 243
(b) ₹ 234
(c) ₹ 240
(d) ₹ 334
Answer:
(b) ₹ 234

Question 5.
If the perimeter of a square is 40 cm, then the length of each side is:
(a) 20 cm
(b) 10 cm
(c) 5 cm
(d) 40 cm
Answer:
(b) 10 cm

Question 6.
The perimeter of a square whose area is 225 m² is:
(a) 15 m
(b) 60 m
(c) 225 m
(d) 30 m
Answer:
(b) 60 m

Question 7.
The area of rectangle is 650 cm² and its breadth is 13 cm. The perimeter of the rectangle is :
(a) 63 cm
(b) 130 cm
(c) 100 cm
(d) 126 cm
Answer:
(d) 126 cm

Question 8.
How many envelopes can be made out of a sheet of paper 72 cm by 48 cm, if each envelope requires a paper of size 18 cm by 12 cm?
(a) 4
(b) 8
(c) 12
(d) 16
Answer:
(d) 16

Question 9.
If the ratio between the length and the perimeter of a rectangular plot is 1: 3, then the ratio between the length and breadth by the plot is :
(a) 1 : 2
(b) 2 : 1
(c) 3 : 2
(d) 2 : 3
Answer:
(c) 3 : 2

Fill in the blanks

Question 1.
1 km is equals to .................... metre.
Answer:
1000

Question 2.
Perimeter of rectangle is 2 × (length + .....................).
Answer:
breadth

Question 3.
The length and breadth of rectangle are 12 cm and 15 cm respectively, then its diagonal is .....................
Answer:
13 cm

Question 4.
The measurement of the region enclosed by a closed plane figure is called the ..................... of the plane figure.
Answer:
area

State whether True or False

Question 1.
Perimeter of an equilateral triangle is 3 times the length of each side of the triangle.
Answer:
True

Question 2.
The perimeter of regular hexagon is 6 side.
Answer:
True

Question 3.
The area of a square whose side is 16 cm, is 64 cm².
Answer:
False

Question 4.
A curve having the same beginning and ending point is called a dosed curve.
Answer:
True

Very Short Answer Type Questions

Question 1.
Find the perimeter of a rectangle whose length and breadth are 15.4 m and 3.2 m respectively.
Answer:
Length of the rectangle = 15.4 m
Breadth of the rectangle = 3.2 m
∴ Perimeter of rectangle
= 2 (length + breadth)
= 2 (15.4 +3.2) m
= 2 × 18.6 = 37.2 m.

Question 2.
Find the perimeter of a square, each of whose side measures 6.3 cm.
Answer:
Each side of a square = 6.3 cm
Perimeter of a square
= 4 × side = 4 × 6.3 = 25.2 cm.

Question 3.
Find the area of rectangle whose length and breadth are 8.2 cm and 5.2 cm respectively.
Answer:
Length of rectangle = 8.2 cm
Breadth of rectangle = 5.2 cm
∴ Area of a rectangle = length + breadth
= 8.2 cm + 5.2 cm = 13.4 cm².

Question 4.
Find the area of a square whose sides is 7 cm.
Answer:
Side of a square = 7 cm
Area of a square = (side)²
= (7)² = 49 cm².

Short Answer Type Questions

Question 1.
The length and breadth of a rectangle are in the ratio 5 : 4 and its perimeter is 144 cm. Find its dimensions.
Answer:
Let the length and breadth of rectangle are 5x and 4x respectively.
∵ Perimeter of rectangle = 144 cm = 5
⇒ 2(l + b) = 144
⇒ 2(5x + 4%) = 144
⇒ 2 × 9x = 144
⇒ l8x = 144
∴ x = \(\frac{144}{18}\) = 8
Hence, Length of a rectangle
= 5x = 5 × 8 = 40 cm.
Breadth = 4x = 4 × 8 = 32cm.

Question 2.
The cost of fencing a rectangular field at ₹ 7.50 per metre is ₹ 600. If its length is 24 m, find its breadth.
Answer:
Total cost of fencing = ₹ 600
Rate of fencing = ₹ 7.50/metre
∴ Perimeter of the field
= \(\frac{\text { Total cost }}{\text { Rate/m }}\) = \(\frac{600}{7.5}\) m
= 80 m
Let the breadth of the field = x metre
∵ Perimeter = 80
⇒ 2(24+ x) =80
⇒ 48 + 2x = 80
⇒ 2x = 80 - 48 = 32
∴ x = \(\frac{32}{2}\) = 16
Hence, the breadth of the field = 16 m.

Question 3.
The cost of constructing a boundary wall of a square field at ₹ 25/ metre is ₹ 1,600. Find the length of each side of the field.
Answer:
Total cost of constructing boundary wall = ₹ 1,600
Rate of construction = ₹ 25/metre
So, Perimeter of a square
= \(\frac{\text { Total cost }}{\text { Rate } / \mathrm{m}}\) = \(\left(\frac{1600}{25}\right)\) = 64 m
Let the length of each side of square = x m
Then, its perimeter =; 64 m
⇒ 4 × side = 64 m
⇒ side = \(\frac{64}{4}\)m = 16m.
Hence, length of each side of the field = 16 m